A uniform rod of mass `m=5.0kg` and length `l=90cm` rests on a smooth horizontal surface. One of the ends of the rod is struck with the impulse `J=3.0N*s` in a horizontal direction perpendicular to the rod. As a result, the rod obtains the momentum `p=3.0N*s`. Find the force with which one half of the rod will act on the other in the process of motion.