A car weighing 550 kg, ascends a hill with a gradient of 1 in 6 at a speed of 36 kmph. Find how much work is done per second, (a) in moving the car up the hill overcoming a total force of friction and air resistance equal to 350 kgwt.

A motor car weighing 1000 kg moves up an incline rising 1 in 49 at the rate of 54 km/hr. Find the power at which the engine is working .

A car weighing 1120kg is going up an incline of 1 in 56 at the rate of 20m in 2s . Find the power of the engine if frictional force is 64N .

A car weighing 500 kg climbs up a hill of slope 1 in 49 with a velocity of 36 KMPH. If the frictional force is 50 N, the power delivered by the engine is

A truck can move up a road which has a gradient of 1 m rise every 50 m with a speed of 24 kmph ? How fast will the same truck move down the hill with the same horse power ? The air resistance to the motion of the truck is 1/25 of its weight.

How much work should be done on a bicycle of mass 20 kg to increase its speed from 2 ms^(-1) to 5ms^(-1) ? (Ignore air resistance and friction).

According to work energy theorem or work energy principle, work done by net force in displacing a body is always equal to change in K.E. of the body. Similarly , if some work is drawn from the body, K.E. of the body decreases by the same amount. In either process, we assume that potential energy of the body does not change. Read the above passage and answer the following question: (i) A car weighing 500 kg is running at a speed of 72 km//h . In how much distance will it stope by applying a braking force of 4000N? (ii) What are the implication of this theorem in day to day life ?

A car weighing 1400 kg is moving at speed of 54 km/h up a hill when the motor stops. If it is just able to read the destination which is at a height of 10 m above the point calculte the work done against friction (negative of the work done by the friction).