`9-0.bar(9)=…………`

The unit vector parallel to the vecotr bar(a)-bar(b) is ……………. where bar(a)=(1,2,-3) and bar(b)=(-2,-4,-9)

The value of 0.bar2+0.bar3+0.bar4+0.bar9+0.bar(39) is

The value of 0.bar(2)+0.bar(3) +0.bar(4)+0.bar(9) +0.bar(39) is

Find the value of 2.bar(6)-0.bar(9) .

If 4bar(a)+5bar(b)+9bar( c )=0 then (bar(a)xx bar(b))xx[(bar(b)xx bar( c ))xx(bar( c )xx bar(a))] = ………..

What is the difference between 0.bar(9) and 0.9 ?

Evaluate 2.bar(6)+0.bar(9)

Show that 0.bar9 = 1

(0.bar1)^(2)[1-9(0.bar(16))^(2)]=?