Home
Class 12
CHEMISTRY
The amount (in grams) of sucrose (mol.wt...

The amount (in grams) of sucrose (mol.wt. = 342g) that should be dissolved in 100 g water in order to produce a solution with a `105.0^@C` difference between the boiling point and freezing point is (Given that `k_f=1.86Kkgmol^(-1) and k_b=0.52Kkgmol^(-1)" for water")` Report your answer by rounding it up to to the nearest whole number.

Promotional Banner

Similar Questions

Explore conceptually related problems

How many grams of sucrose (molecular mass 342) should be dissolved in 100 g water in order to produce a soluton having difference between the boiling point and freezing point equal to 105^@C ? (K_b=0.512 Km^-1, K_f=1.86Km^-1) .

How many grams of sucrose (molecular weight 342) should be dissolved in 100 g water in order to produce a solution with 105^(@)C difference between the freezing point and the boiling point ? (K_(b) =0.51^(@)C m^(-1) , (K_(f) =1.86^(@)C m^(-1))

How many grams of sucrose (molecular weight 342) should be dissolved in 100 g water in order to produce a solution with 105^(@)C difference between the freezing point and the boiling point ? (K_(b) =0.51^(@)C m^(-1) , (K_(f) =1.86^(@)C m^(-1))

How many grams of sucrose (molecular weight 342) should be dissolved in 100 g water in order to produce a solution with 105^(@)C difference between the freezing point and the boiling point ? (K_(b) =0.51^(@)C m^(-1) , (K_(f) =1.86^(@)C m^(-1))

How many grams of sucrose should be dissolved in 100g water in order to produce a solution having difference between the free zing point and the boiling point temperatures at 105.0^@C

How many moles of sucrose should be dissolved in 500 g of water so as to get a solution which has a difference of 104^(@)C between boiling point and freezing point ? ( K_(f) = 1.86 K kg mol^(-1) , K_(b) = 0.52 K kg mol^(-1) )

How many moles of sucrose should be dissolved in 500 g of water so as to get a solution which has a difference of 103.57^(@)C between boiling point and freezing point :- (K_(f)=1.86" K kg mol"^(-1), K_(b)="0.52 K kg mol"^(-1))