The sum of father's age and twice the age of his son is 70. If we double the age of the father and add it to the age of his son the sum is 95. Find their present ages.

10 years ago, the age of a father was four times the age of his son then. 10 years hence, the age of the father will be twice the age of his son. Find their present ages.

The age of father is equal to the square of the age of his son. The sum of the age of the father and five times the age of the son is 66 years. Find their ages.

The present age of father is four times the age of his son. After 10 years, age of father will become three times the age of his son. Find their present ages.

The age of the father is double to his son's age. Sum of their ages is 57. The age of his son is

The sum of ages of father and his son is 75 years.If the age of the son is 25 years find the age of the father.

The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:

The age of a father is twice the square of the age of his son. Eight years hence, the age of his father will be 4 years more than 3 times the age of the son. Find their present ages.

The age of a father is twice the square of the age of his son. Eight years hence, the age of his father will be 4 years more than 3 times the age of the son. Find their present ages.