Home
Class 12
CHEMISTRY
A sample of AgCI was treated with 5.00mL...

A sample of AgCI was treated with `5.00mL` of `1.5M` `Na_(2)CO_(3)` solubility to give `Ag_(2)CO_(3)` . The remaining solution contained `0.0026g of CI^(-)` per litre. Calculate the solubility product of AgCI. `(K_(SP)for Ag_(2)CO_(3)=8.2xx10^(-12))`

Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the solubility of Ag_(2)CrO_(4) in 0.1M AgNO_(3)K_(sp) of Ag_(3)CrO_(4)=1xx10^(-22)

Solubility of AgCI at 20^@C is 1.435 xx 10^-3g per litre. The solubility product of AgCI is

The expression for the solubility product of Ag_(2)CO_(3) will be :

Solubility of Ag_(2)CrO_(4) is 8 xx 10^(-5) mol L^(-1) . Calculate the solubility product.

The solubility product of silver chloride is 1.2xx10^(-10) at 298K. Calculate the solubility of AgCI at 298K.

K_(sp) of AgCI is 1.8xx10^(-10). Calculate molar solubility in 1M AgNO_3 .