Consider a twon with n people. A person spreads a rumour to a second, who in turn repeats it to a third and so on. Supppose that at each stage, the recipient of the rumour is chosen at random from the remaining (n-1) people. The probability that the rumour will be repeated n times without being repeated to the originator is

Three numbers are selected at random without replacement from the set of numbers {1,2,….n}. The conditional probability that the third number lies between the first two, if the first number is known to be smaller than the second is

Direction: Study the following information carefully and answer the following questions. An uncertain number of person is sitting in a row facing towards North. L is sitting second from the left end. W is sitting third from the right end. The number of the person sitting right of U is the same as the number of people sitting left of M. V is sitting third to the left of U. Number of people sitting between W and U is one more than the number of people sitting right of W. N is an immediate neighbor of V, but not immediate to M. There are four-person sitting between M and U. Who is sitting sixth to the right of N?

Statement-1 : An urn contains m white and n black balls. All the balls except for one ball, are draw from it. The probability that the last ball remaining in the urn is white is equal to m/(m+n) . Statement-2 : An urn contains m white balls and n black balls. Balls are drawn one by one till all the balls are drawn. The probability that the second drawn ball is white is n/(m+n) . Statement-3 : An urn contains 6 balls, 3 white and 3 black ones, a person selected at random an even number of balls (all the different ways of drawing an even number of balls are considered equally probable, irrespective of their number). Then the probability that there will be the same numberof black and white balls among them is 11/15 .

Statement-1 : An urn contains m white and n black balls. All the balls except for one ball, are draw from it. The probability that the last ball remaining in the urn is white is equal to m/(m+n) . Statement-2 : An urn contains m white balls and n black balls. Balls are drawn one by one till all the balls are drawn. The probability that the second drawn ball is white is n/(m+n) . Statement-3 : An urn contains 6 balls, 3 white and 3 black ones, a person selected at random an even number of balls (all the different ways of drawing an even number of balls are considered equally probable, irrespective of their number). Then the probability that there will be the same numberof black and white balls among them is 11/15 .