" The area enclosed by the curve "y=sin x,y=0,x=0" and "x=(pi)/(2)" is "

The area enclosed by the curve y=sin^(3)x between x=0 and x=pi/2

The area enclosed by the curves y = cos x, y = 1+sin 2x and x= (3pi)/2 as x varies from 0 to (3pi)/2 , is

The area of the region enclosed by the curves y= sin x, y = cos and x=0 , x = (3pi)/(2) is ……Sq. units.

The area enclosed by the curves y=8x-x^(2) and 8x-4y+11=0 is

Find the area of the region enclosed by the given curves . y=sinx ,y=cosx , x=0 , x=(pi)/(2)

Find the area of the region enclosed by the given curves . y=sinx ,y=cosx , x=0 , x=(pi)/(2)

The area enclosed by the curve |y|=sin2x, where x in [0,2pi]. is

The area enclosed by the curve |y|=sin2x, where x in [0,2pi]. is

Find the area enclosed between y= sin 2x,y= sqrt3 sin x, x = 0 and x= (pi)/(6)