`m^2+n^2+2mn-121`

Add the following expressions: 3n^(2)+5mn-6m^(2), 2m^(2)-3mn -4n^(2), 2mn-3m^(2)-7n^(2)

If m and n are two distinct numbers such that m >n, then prove that m^2-n^2 ,2mn and m^2+n^2 is a Pythagorean triplet.

Factories the following : m^(2) + 2mn - 24n^(2)

Add the following: l^2 + m^2 , m^2+n^2 , 2lm+2mn+2nl

Which polynomial should be subtracted from 3m^2 n +5mn^2 -2m^2 n^2 to get the polynomial -m^2 n +7mn^2 +4m^2 n^2 .

What should be subtracted from -7mn + 2m^2 + 3n^2 " to get " m^2 + 2mn + n^2 ?

Add the following terms: 4m^2-7n^2+5mn , 3m^2+5n^2-2mn

if m+n=5 and mn= 6, but (m^2 + n^2) (m^3 + n^3) = how much?