int(x^(49)tan^(-1)(x^(50)))/((1+x^(100)))dx=k(tan^(-1)(x^(50)))^(2)+c rArr k=

int(x^(49)tan^(-1)(x^(50)))/((1+x^(100)))dx=k[tan^(-1)(x^(50))]^(2)+C, , then k is equal to

int_( then k)^( if )(x^(49)tan^(-1)(x^(50)))/(1+x^(100))dx=k*[tan^(-1)(x^(50))]^(2)+c

int (x^(49) tan^(-1)x^(50))/(1+x^(100)) dx = k[tan^(-1)(x^(50)]^(2) + c then k =

int_( then )^((x^(49)tan^(-1)x^(50))/(1+x^(100)))1+x^(100)dx=k[tan^(-1)(x^(50))]^(2)+C

int(tan^(-1)x+x+tan^(-1)((1)/(x)))dx =

int_(-1)^(3)(Tan^(-1)""(x)/((x^(2)+1))+Tan^(-1)""(x^(2)+1)/(x))dx=

The vlaue of ((5050)int_(0)^(1)(1-x^(50))^(100)dx)/(int_(0)^(1) (1-x^(50))^(100)dx) , is

If int (x^(2)-a^(2))/(x^(2)+a^(2))dx=x+k "tan"^(-1)(x)/(a)+c then k=

If int((x^(2)-1)dx)/((x^(4)+3x^(2)+1)Tan^(-1)((x^(2)+1)/(x)))=klog|tan^(-1)""(x^(2)+1)/x|+c , then k is equal to