" If "sin9 theta=sin theta," then "theta=

If sin 6theta = sin 4theta - sin 2theta , then theta =

If" " 0 < theta < pi/2, " then show that " sin theta sin 2 theta sin 3 theta le 9/16

Solve : sin 9 theta = sin theta.

(sin 3 theta + sin 5 theta + sin 7 theta + sin 9theta)/(cos 3 theta + cos 5 theta + cos 7 theta + cos 9 theta )=

The value of (sin 3theta+sin 5theta+sin 7 theta+sin 9 theta)/(cos 3 theta+cos 5 theta+cos 7 theta+cos 9 theta)=……………

(sin 3 theta + sin 5 theta + sin 7 theta + sin 9theta)/(cos 3 theta + cos 5 theta + cos 7 theta + cos 9 theta )=

If 1+sin theta=9cos theta and 0^(@)

[[ Simplify :cos thetacos theta,sin theta-sin theta,cos theta]]+sin theta[[sin theta,-cos thetacos theta,sin theta]]