Two oxides of a metal (M) contain 22.53% and 30.38% of oxygen. If the second oxide be `M_(2)O_(3)`, find the formula of first oxide.

If the oxides of a metal contain 78.7% and 64.5% of oxygen and if the formual of the first oxides is MO, find the formula of other oxide, the ratio of oxygen in two oxides is 1:3.

The percentages of oxygen in two oxides of a metal are 22.2 and 30 respectively. The formula of the second oxide is M_2O_3 . Deduce the formula of first.

Two oxides of a metal contain 27.6% and 30.0% of Oxygen, respecttively. If the formula of the first be M_(3) O_(4) . Find that of the second.

Two oxides of a metal contain 27.6% and 30.0% of Oxygen, respecttively. If the formula of the first be M_(3) O_(4) . Find that of the second.

Two oxides of a metal contain 27.6% and 30.0% of Oxygen, respecttively. If the formula of the first be M_(3) O_(4) . Find that of the second.

Two oxides of a metal contain 27.6% and 30.0% of Oxygen, respecttively. If the formula of the first be M_(3) O_(4) . Find that of the second.

Two oxides of metal M have 27.6% and 30% oxygen by weight. If the formula of the first oxide is M_(3)O_(4) what is the formula of second oxide?

Two oxides of a metal contain 36.4% and 53.4% of oxygen by mass respectively. If the formula of the first oxide is M_(2)O , then that of the second is