`300 J`of work is done in slide a `2kg` block up an inclined plane of height `10m`. `Taking g = 10 m//s^(2), work done against friction is

300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Taking, g = 10 m//s^2 , work done against friction is________.

300J of work is done in slinding a 2 kg block up an inclined plane of height 10m. Taking g = 10m//s^(2) , work done against friction is

300J of work is done in slinding a 2 kg block up an inclined plane of height 10m. Taking g = 10m//s^(2) , work done against friction is

If 250 J of work is done in sliding a 5 kg block up an inclined plane of height 4 m. Work done against friction is (g=10ms^(-2))

If 250 J of work is done in sliding a 5 kg block up an inclined plane of height 4 m. Work done against friction is (g=10ms^(-2))

If 250 J of work is done in sliding a 5 kg block up an inclined plane of height 4 m. Work done against friction is (g=10ms^(-2))

500 J of work is done in sliding a 4 kg block up along a rough inclined plane to a vertical height of 10 m slowly. The work done against friction is (g = 10 m/s^2)