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Calculating conductivity and molar condu...

Calculating conductivity and molar conductivity: Resistance of a conductivity cell filled with `0.1 M KCl` solution is `100 Omega`. If the resistance of the same cell when filled with `0.02 M KCl` solutions `520 Omega` and the conductivity of `0.1 KCl` solution is `1.29 S m`, calculate the conductivity and moalr conductivity of `0.02 M KCl` solution.
Strategy : Calculate the cell constant with the help of `0.01 M KCl` solution (both `R` and `kappa` are Known). Use the cell constant to determine the conductivity of `0.02 M KCl` solution and finally find its molar conductivity using the molarity

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Resistance of a conductivity cell filled with "0.1 mol.L"^(-1)KCl solution is 100Omega . If the resistance of the same cell when filled with "0.02 mol.L"^(-1).KCl solution is 520Omega, calculate the conductivity and molar conductivity of "0.02 mol.L"^(-1) The conductivity of 0.1(M) KCl solution is "1.29S.m"^(-1).

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The resistance of a conductivity cell filled with 0.1 M KCl solution is 100 Omega . If R of the same cell when filled with 0.02 M KCl solution is 520 Omega , calculate the conductivity and molar conductivity of 0.02 M KCl solution. The conductivity of 0.1 M KCl solution is 1.29 S m^(-1) .