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Let A= R- (3), B= R-{1}. Let f: A to B b...

Let `A= R- (3), B= R-{1}`. Let `f: A to B` be defined by `f(x)= ((x-2)/(x-3)) AA x in A`. Then show that `f` is bijective. Hence find `f^(-1) (x)`.

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Verified by Experts

The correct Answer is:
`f^(-1) (x) = (3x-2)/( x-1) = g(x)`.
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