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Let f: W ->Wbe defined as f(n) = n - 1,...

Let `f: W ->W`be defined as `f(n) = n - 1`, if is odd and `f(n) = n + 1`, if n is even. Show that f is invertible. Find the inverse of f. Here, W is the set of all whole numbers.

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The correct Answer is:
`f^(-1) (x) = {{:(x-1",", "if n is odd"),(x+1",","if n is even"):}`
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