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Consider f: Rvec[-5,oo) given by f(x)=9x...

Consider `f: Rvec[-5,oo)` given by `f(x)=9x^2+6x-5` . Show that `f` is invertible with `f^(-1)(y)=((sqrt(y+6)-1)/3)dot`

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The correct Answer is:
`f^(-1) = g= (sqrt(y+6) -1)/( 3)`
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