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The area of a triangle with vertices (-...

The area of a triangle with vertices `(-2,0),(0,k)` and `(0,4)` is `4` square units.Then the values of `K` will be

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If the area of the triangle with vertices (-2, 0), (0, 4) and (0, k) is 4 square units, find the values of k u"sin"g determinants.

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Knowledge Check

  • The area of a triangle with vertices (-3,0),(3,0) and (0,k) is 9 sq. units . The value of k will be :

    A
    9
    B
    3
    C
    `-9`
    D
    6

  • If the area of the triangle with vertices (x, 0). (1.1) and (0.2) is 4 square units then a value of

    A
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    B
    `-4`
    C
    `-6`
    D
    8

  • The area of triangle with vertices (K, 0), (4,0), (0, 2) is 4 square units, then value of K is

    A
    8
    B
    0 or -8
    C
    0
    D
    0 or 8

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    If area of the triangle with vertices (-2, 0), (0, 4) and (0, k) is 4 square units, find the value of 'k' using determinants.

    If the area of the triangle with vertices (2,-6),(5,4) and (K,4) is 35 sq. units, then find the values of K, using determinants.

    The area of the triangle with vertices at (-4,1) , (1,2),(4,-3) is

    If the area of the triangle with vertices (2,-6), (5,4) and (k,4) is 35 square units, find values of k using determinants.

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