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A parallel plate capacitor with only air...

A parallel plate capacitor with only air between the plates has a capacitance of `8pF`. What will be the capacitance if the distance between the plates is reduced by half and the space between them is filled with a substance of dielectric constant 6?

Text Solution

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`C_0 = (A epsi_0)/(d) = 8pF`
When the distance is reduced to half and dielectric medium fills the gap, the new capacitance will be
` C = (epsi_r Aepsi_0)/(d//2) = (2 epsi_r A epsi_0)/(d)`
` = 2 epsi_r C_0`
`C = 2 xx 6 xx 8 = 96 pF`
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