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An a.c. source of 220 V 50 Hz is connect...

An a.c. source of 220 V 50 Hz is connected in series with a `50 Omega` resistance `150 mu F` capacitors and 0.5 H inductor in series. Calculate the current through the combination.

Text Solution

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`Z = sqrt(R^(2) + (X_(L) - X_(C ))^(2))`
`X_(L) = 2pifL = 157 Omega`
`X_(C ) = (1)/(2pi fC) = 21.23 Omega`
To find `Z = 144.68 Omega`
`I = (V)/(Z) = (220)/(144.68) = 1.52 A`
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