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A wheel with 8 metallic spokes is 50 cm ...

A wheel with 8 metallic spokes is 50 cm long is rotated with the speed of 120 rev/min in a plane normal to the horizontal component of the earth magnetic field. The Earth's magnetic field at the place of 0.4 G and the angle of dip is `60^(@)`. Calculate the emf induced between the axel and the rim of the wheel. How will the value of emf be affected if the number of spokes were increased.

Text Solution

Verified by Experts

`H = B cos theta = 0.4 cos 60^(@)`
`= 0.2 G = 0.2 xx 10^(-4)T`
This component is parallel to the plane of the wheel. Thus, the emf induced is
`E = (1)/(2) Bl^(2) omega`, where `omega = (2pi N)/(t)`
`:. E = (1)/(2) xx 0.2 xx 10^(-4) xx (0.5)^(2) xx (2 xx 3.14 xx 120)/(60)`
`= 3.14 xx 10^(-5) V`.
The value of emf will not be affected if number of spokes were increased.
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A wheel with 10 metallic spokes each 0.5 m long is rotated with a speed of 120 rev/min in a plane normal to the horizontal component of earth’s magnetic field H_E at a place. If H_E = 0.4 G at the place, what is the induced emf between the axle and the rim of the wheel? Note that 1 G = 10^(-4) T.

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Knowledge Check

  • At certain place , the horizontal component of earth's magnetic field is 3.0 . The magentic field of earth at that location

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    zero everywhere
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    varying from place to place on the Earth' s surface
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