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Show that 1 amu = 932 MeV....

Show that 1 amu = `932 MeV`.

Text Solution

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(i) The difference between the Rest mass of a nucleus and the sum of the masses of its constituents is called Nuclear-mass defect.
(ii) The ratio of the Binding energy to a nucleus to the number of nucleons or binding energy per nucleon, of a nucleons is called specific binding energy.
From Einstein.s mass-energy equation.
`E=mc^(2)`
Where m=mass defect
& c= speed of light.
here m=1a.m.u
`=1.6xx10^(-27)kg`
`E=1.66xx10^(-27)xx(3xx10^(8))J`
`:. E=(1.66xx10^(-27)xx9xx10^(16))/(1.6xx10^(-19))eV`
`=(1.66xx9)/(1.6)xx10^(8)eV`
`=(1.66xx9)/(1.6)xx100 MeV`
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