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The wavelength of first line in Balmer s...

The wavelength of first line in Balmer series is 6563 Å. Calculate the longest and the shortest wavelengths of the first spectral lines in the Lyman series.

Text Solution

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`(1)/(lambda)=R[(1)/(n_(f)^(2))-(1)/(n_(i)^(2))]`
For First line of Balmer series
`n_(f)=2 and n_(i)=3`
`(1)/(lambda_(B_(2)))=R[(1)/(4)-(1)/(9)]=(5R)/(36)`
For Longest wavelength of Lyman series
`(1)/(lambda_(L_(1)))=R[1-(1)/(4)](3R)/(4)` to find `lambda_(L_(1))=1215Å`
For shortest wavelength of Lyman series
`n_(f)=1 and n_(i)=oo`
`lambda_(L_(oo))=911.54Å`
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