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A transistor is connected in CE configur...

A transistor is connected in CE configuration. The voltage drop across the load resistance (`R_C`) 3 ks is 6 V. Find the base current. The current gain `alpha` of the transistor is 0.97 Data : Voltage across the collector load resistance (`R_C`) = 6 V .
` alpha = 0.97 : R_C = 3 k Omega`

Text Solution

Verified by Experts

The voltage across the
collector resistance is `R_C = I_C R_C = 6V `
hence `I_C =(6 )/(RC ) = ( 6 )/( 3 xx 10^3) =2mA`
current gai ` beta = (a)/( 1-a) = ( 0.97 )/( 1-0.97 ) = 32.33`
` therefore I_B= (I_C )/(beta) = ( 2 xx 10^(-3))/( 32.33 )= 61.86 mu A`
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