दिखाएँ कि दो सदिशों ` bar a ` तथा ` bar b ` की लिए सदैव ` | bar a + bar b | lt | bar a | + |bar b | ` होते हैं |

bar a, bar b, bar c are three vectros, then prove that: (bar a xx bar b) xx bar c = (bar a. bar c) bar b-(bar b. bar c) bar a.

(d) answer ANY one question :1. bar a, bar b and bar c be three vectors such that bar a +bar b+ bar c =0 and |bar a|=1, |bar b|=4,|bar c |=2 . Evlautae bar a.bar b + bar b.bar c+bar c.bar a .

The non-zero vectors bar(a) , bar(b) , bar(c ) holds | (bar(a) .bar(b) ).bar( c) |=| bar(a) ||bar(b)|| bar( c) if

If bar(a) is perpendicular to bar(b) then bar(a)*bar(b) is

Compute bar(a) xx (bar(b) + bar(c )) + bar(b) xx (bar(c ) +bar(a)) + bar(c ) xx (bar(a)+bar(b))