" iv) "" वक्र "(x^(2))/(8)+(y^(2))/(6)=1" के बिन्दु "(2,1)" पर "

In the ellipse (x^(2))/(6)+(y^(2))/(8)=1 , the value of eccentricity is

(pi)(8y^(2)+6y+1)#(2y+1)

x ^ (2) + y ^ (2) + 1, x ^ (2) + 2y ^ (2) + 3, x ^ (2) + 3y ^ (2) + 4y ^ (2) + 2,2y ^ (2) + 6.3y ^ (2) + 8y ^ (2) + 1.2y ^ (2) + 3.3y ^ (2) +4] |

(2x - 6y)^(2) - (6y + 8x)^(2) = "________"

Equation of the circle which passes through the points of intersection of circles x ^(2) +y^(2) =6 and x^(2)+y^(2) -6x +8 =0 and the point (1,1) is-

Show that the circles x^(2) + y^(2) + 6x + 2y + 8 = 0 and x^(2) + y^(2) + 2x + 6y + 1 = 0 intersect each other.

If (1 - y) (1 + 2x + 4x^(2) + 8x^(3) + 16x^(4) + 32x^(5) ) = 1 -y^(6), (y ne 1) , then a value of y/x is