" 3."[[sin20^(@),-cos20^(@)],[sin70^(@),...

" 3."[[sin20^(@),-cos20^(@)],[sin70^(@),cos70^(@)]]=?

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cos70^(@)+sin40^(@)=

cos70^(@)+sin40^(@)=

|["cos"70^(@), "sin"20^(@)], ["sin"70^(@), "cos"20^(@)]|=?

Write the value of |[sin20^@-cos20^@ ],[sin70^@ cos70^@]| .

(2cos40^(@)-cos20^(@))/(sin20^(@))

(2cos40^(@)-cos20^(@))/(sin20^(@))

sin 70^@ - cos 40^(@) =

sec70^(@)sin20^(@)+cos20^(@)cosec70^(@)=2

sec70^(@)sin20^(@)+cos20^(@)"cosec"70^(@)=?

(sin70^(@)+cos40^(@))/(cos70^(@)+sin40^(@))

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