" (iii) "(4x-3)^(2)-2(x+3)=0

If the equation (4x-3)^(2)-2(x+3)=0 is expressed in the form ax^(2)+bx+c=0(ane0) then the value of a is

Use the substitution y=2x+3 to solve for x, if 4(2x+3)^(2)-(2x+3)-14=0 .

Solve equations, number 1 to number 20 , given below, using factorisation method : 4(2x-3)^(2)-(2x-3)-14=0

Solve: (i) 3x^(2)-4x+(20)/(3)=0 . (ii) x^(2)-2x+(2)/(3)=0 .

Find the roots of the quadratic equations by applying the quadratic formula.(i) 2x^(2)-7x+3=0 (ii) 2x^(2)+x-4=0 (iii) 4x^(2)+4sqrt(3)x+3=0( iv )2x^(2)+x+4=0

The equation whose roots are diminished by 1 than those of 4x^(3)-x^(2)+2x-3=0 is (A) 4x^(3)-11x^(2)+12x+2=0 (B) 4x^(3)-11x^(2)+12x-3=0 (C) 4x^(3)+11x^(2)+12x+2=0 (D) 4x^(3)+11x^(2)+12x-3=0

The biquadratic equation, two of whose roots are 1+i , 1-sqrt(2) is A) x^(4)-4x^(3)+5x^(2)-2x-2=0 B) x^(4)-4x^(3)-5x^(2)+2x+2=0 C) x^(4)+4x^(3)-5x^(2)+2x-2=0 D) x^(4)+4x^(3)+5x^(2)-2x+2=0

If x - 1 is a factor of x^(5) - 4x^(3) +2 x^(2) - 3x + k = 0 then k is

4 (2x-3) ^ (2) - (2x-3) -14 = 0