A ball of mass 1 kg carrying a charge `10^(-8)C` moves from a point A at potential 600 V to a point B at zero potential. The change in its kinetic energy is

A bal of mass 1 g carrying a chage 10^-8 C moves from a point A at potential 600 V to a point B at zero potential. The change in its K.E. is

A particle having mass 1 g and electric charge 10^(-8) C travels from a point A having electric potential 600 V to the point B having zero potential. What would be the change in its kinetic energy ?

A ball of mass 1g and charge 10^(-8) C moves from a point A whose potential is 600V to the point B whose potential is zero. Velcoity of the ball at the point B is 20 cm s^(-1) . The velocity of the ball at the point is

A ball of mass 1g and charge 10^(-8) C moves from a point A . Where potential is 600 volt to the point B where potential is zero. Velocity of the ball at the point B is 20 cm//s . The velocity of the ball at the point A will be

A ball of mass 1g and charge 10^(-8) C moves from a point A . Where potential is 600 volt to the point B where potential is zero. Velocity of the ball at the point B is 20 cm//s . The velocity of the ball at the point A will be

On moving a charge of 2C from a point A where potential is +12V to a point B where potential is -12 V, the work done is -

On moving a charge of 2C from a point A where potential is +12V to a point B where potential is -12 V, the work done is -