`((1+costheta+isintheta)/(1+costheta-isintheta))^(n)`

(1+costheta+isintheta)^(n)+(1+costheta-isintheta)^(n)

(1-costheta+isintheta)^(6)

(1+costheta-isintheta)^4 =

(cos3theta+isin3theta)^5/(costheta+isintheta)^6

(costheta+isintheta)^(10)+(costheta-isintheta)^(10)

Prove that (1+costheta+isintheta)^(n)+(1+costheta-isintheta)^(n)=2^(n+1)cos^(n)((theta)/(2))cos((ntheta)/(2))

Assertion (A) : (Costheta+iSintheta)^(10)+(Costheta-iSintheta)^(10)=2cos10theta Reason (R) : (1+costheta+isintheta)^n+(1+costheta-isintheta)^n= 2^(n+1)cos^n(theta/2)cos((ntheta)/(2))

(1-costheta+isintheta)^8 =

(1-costheta+isintheta)^6 =