Directrix of a parabola is x + y = 2. If it’s focus is origin, then latus rectum of the parabola is equal to

The directrix of a parabola is 2x-y=1. The focus lies on y-axis.The locus of one end of the latus rectum is

The line x-1=0 is the directrix of a parabola, y^2=kx then Find the vertex, focus,axis of parabola and length of latus rectum of the parabola.

Find vertex, focus, directrix and latus rectum of the parabola y^(2)+4x+4y-3=0 .

Find vertex, focus, directrix and latus rectum of the parabola y^(2)+4x+4y-3=0 .

If vertex of a parabola is origin and directrix is x + 7 = 0 , then its latus rectum is

Find the vertex, focus, directrix, axis and latus-rectum of the parabola y^2=4x+4ydot

Find the vertex, focus, directrix, axis and latus-rectum of the parabola y^2=4x+4ydot

Find the vertex, focus, axis, directrix and latus rectum of that parabola : y^2 - 3x - 2y+7=0

Find the vertex, focus, axis, directrix and latus rectum of that parabola : y^2 - 3x - 2y+7=0

Find the vertex, focus, axis, directrix and latus rectum of that parabola : (y-2)^2 = 3 (x+1)