" The trajectory of a projectile is given by "y=sqrt(3)x-g(x^(2))/(2)" .The angle of projection is "

The equation of trajectory of an oblique projectile y = sqrt(3) x - (g x^(2))/(2) . The angle of projection is

The equation of trajectory of an oblique projectile y = sqrt(3) x - (g x^(2))/(2) . The angle of projection is

The equation of a projectile is y=sqrt(3)x-(gx^(2))/(2) the angle of projection is:-

The equation of a projectile is y=sqrt(3)x-(gx^(2))/(2) the angle of projection is:-

The equation of a projectile is y=sqrt(3)x-(gx^(2))/(2) the angle of projection is:-

A particle is projected in x-y plane with y- axis along vertical, the point of projection being origin. The equation of projectile is y = sqrt(3) x - (gx^(2))/(2) . The angle of projectile is ……………..and initial velocity is ………………… .