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[" 11.Under the action of a force,a "2kg...

[" 11.Under the action of a force,a "2kg" body moves such that its position "x" as a function of time is given by "],[x=(t^(3))/(3)," where "x" is in meter and "t" is in second.The work done by the force in the first two second is "],[[" (a) "1600J," (b) "160J," (c) "16J," (d) "1.6J]]

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