7.5 mL of a hydrocarbon gas was exploded with excess of oxygen. On cooling, it was found to have undergone a contraction of 15 mL. If the vapour density of the hydrocarbon is 14, determine its molecular formula. (C = 12, H = 1)

20 mL of a gaseous hydrocarbon is exploded with excess oxygen in an eudiometer tube and the contraction in volume was 70 mL. Vapour density of the hydrocarbon is 29. Find its molecular formula

3cm^(3) of a gaseous hydrocarbon is exploded with excess of oxygenh. On cooling the mixture, the obseved contraction is found to be 6cm^(3) . Vapour density of the hydrocarbon is 14. what is the molecular formula of the hydrocarbon.

A hydrocarbon contains 17.2% H. If the vapour density is 29, calculate its molecular formula.

A gaseous hydrocarbon contains 82.76% of carbon. Given that its vapour density is 29, find its molecular formula (C = 12, H = 1).

Give the structures of the hydrocarbons corresponding to the molecular formula C_(8)H_(12)

Give the structures of the hydrocarbons corresponding to the molecular formula C_(8)H_(12)

A gaseous hydrocarbon contains 82.76% of carbon. Given that its vapour density is 29,find its molecular formula. [C = 12, H = 1]