`1 "mole of" N_(2) "and" 3 "moles of " H_(2)` are placed in `1L` vessel. Find the concentration of `NH_(3)` at equilibrium, if the equilibrium constant `(K_(c))` at `400K "is" (4)/(27)`

1 mole of N_(2) and 3 mole of H_(2) are mixed in a closed vessel of 1 dm^(3) capacity. At equilibrium if the vessel contains a total of 2.4 moles, calculate equilibrium constant K_(c)" for "N_(2)+3H_(2)hArr2NH_(3) .

In a reaction A+2BhArr2C , 2.0 mole of 'A' , 3.0 mole of 'B' and 1 mole of 'C' are placed in a 2.0 L flask and the equilibrium concentration of 'C' is 1.0 mole/L.The equilibrium constant (K) for the reaction is :

In a reaction A+2B hArr 2C, 2.0 moles of 'A' 3 moles of 'B' and 2.0 moles of 'C' are placed in a 2.0 L flask and the equilibrium concentration of 'C' is 0.5 mol // L . The equilibrium constant (K) for the reaction is

In a reaction A+2B hArr 2C, 2.0 moles of 'A' 3 moles of 'B' and 2.0 moles of 'C' are placed in a 2.0 L flask and the equilibrium concentration of 'C' is 0.5 mol // L . The equilibrium constant (K) for the reaction is

A mixture of 2 moles of N_(2) and 8 moles of H_(2) are heated in a 2 lit vessel, till equilibrium is established. At equilibrium, 04 moles of N_(2) was present. The equilibrium concentration of H_(2) will be

A mixture of 2 moles of N_(2) and 8 moles of H_(2) are heated in a 2 lit vessel, till equilibrium is established. At equilibrium, 04 moles of N_(2) was present. The equilibrium concentration of H_(2) will be

PCl_5 to PCl_3 + Cl_2 K_c = 1.844 If 3 moles of PCl_5 are taken in 1L vessel. Find equilibrium concentration of PCl_5