A car of mass `m` travelling at speed `v` moves on a horizontal track. The centre of mass of the car describes a circle of radius `r`. If `2a` is the separation of the inner and outer wheels and `h` is the height of the centre of mass above the ground, show that the limiting speed beyond which the car will overturn in given by
`v^(2)=(gra)/h`

The distance between the inner and outer wheels of a car is 1.75 m and its centre of gravity is 0-50 m above the ground. What is the maximum speed with which the car can negotiate a curve of radius of 40 m without overturning ?

A car moves with speed v on a horizontal circular track of radius R . A head-on view of the car is shown in figure. The height of the car's centre of mass above the ground h , and the separation between its inner and outer wheel, is d . The road is dry, and the car does not skid. Show that the maximum speed the car can have without overturning is given by v_(max)=sqrt((gRd)/(2h)) . To reduce the risk of rollover, should one increase or decrease h ? Should one increase or decrease the width d of the wheel base?

A car moves with speed v on a horizontal circular track of radius R . A head-on view of the car is shown in figure. The height of the car's centre of mass above the ground is h , and the separation between its inner and outer wheels is d The road is dry, and the car does not skid. The maximum speed the car can have without overturning is : .

A car of mass m moves in a horizontal circular path of radius r metre. At an instant its speed is V m//s and is increasing at a rate of a m//sec^(2) .then the acceleration of the car is