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In the given figure, can you use `ASA` congruence rule and conclude that `/_\AOC cong /_\BOD`?

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In the two triangles `AOC` and `BOD`, `/_C = ∠D` (each `70^@` )
Also, `/_AOC = /_BOD = 30^@` (vertically opposite angles)
So, `/_A` of `/_\AOC = 180^@ – (70^@ + 30^@) = 80^@` (using angle sum property of a triangle)
Similarly, `/_B of /_\BOD = 180^@ – (70^@ + 30^@) = 80^@`
Thus, we have `/_A = /_B, AC = BD` and `/_C = /_D`
Now, side `AC` is between `/_A` and `/_C` and side `BD` is between `/_B` and `/_D`.
So, by `ASA` congruence rule, `/_\AOC cong /_\BOD`.
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