If `f(x)=(25-x^(4))^(1//4)` for `0 lt x lt sqrt5` then `f(f((1)/(2)))=`

If f(x):(25-x^(4))^((1)/(4)) for 0

If f (x) = sin (2x ^(2) -2 [x]) for 0 lt x lt 1, then f ' ((sqrtpi)/(2))=

If f(x)=sqrt(x-2) , for 2 lt x lt 4 , then f(x) is

If f(x)=sqrt(x-2) , for 2 lt x lt 4 , then f(x) is

If f(x)= {{:(,x-5 "for "x le 1),(,4x^(2)-9"for "1 lt x lt 2" then "f'(2^+)),(,3x+4"for "xge2):} =

If f(x)= {{:(,x-5 "for "x le 1),(,4x^(2)-9"for "1 lt x lt 2"then "f'(2+)),(,3x+4"for "xge2):}

If f(x)=-sqrt(25-x^(2))", then " underset(x to 1)"Lt" (f(x)-f(1))/(x-1)=

Let a , b in R,(a in 0) . If the funtion f defined as f(x)={{:(,(2x^(2))/(a),0 le x lt 1),(,a,1 le x lt sqrt2),(,(2b^(2)-4b)/(x^(3)),sqrt2lt x lt oo):} is a continous in [0,oo) . Then, (a,b)=