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If 10 g of ice is added to 40 g of water...

If 10 g of ice is added to 40 g of water at `15^(@)C`, then the temperature of the mixture is (specific heat of water `= 4.2 xx 10^(3) j kg^(-1) K^(-1)`, Latent heat of fusion of ice `= 3.36 xx 10^(5) j kg^(-1)`)

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A piece of ice of mass 100 g and at temperature 0^@ C is put in 200 g of water of 25^@ C . How much ice will melt as the temperature of the water reaches 0^@ C ? (specific heat capacity of water =4200 J kg^(-1) K^(-1) and latent heat of fusion of ice = 3.4 xx 10^(5) J Kg^(-1) ).

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