" A wire of length L and resistance "R" is stretched to get the radius of cross-section halved.What is the new resistance "

Choose correct alternative. The wire of length L and resistance R isstretched so that its radius of cross-section is halved. What is its new resistance?

Write in the form of a formula a relationship between resistance and resistivity of an ohmic conductor. A wire of length ‘l’ and resistance ‘R’ is stretched so that it’s length is doubled and area of cross section is halved. How will its resistance change?

Write in the form of a formula a relationship between resistance and resistivity of an ohmic conductor. A wire of length ‘l’ and resistance ‘R’ is stretched so that it’s length is doubled and area of cross section is halved. How will its resistivity change . Justify your answer in each case.

A wire is of resistance R is stretched, so that its radius decreases b factor n. Calculate its new resistance.

A given piece of wire of length l and radius r and resistance R is stretched uniformly to wire of radius (r)/(2) .Its new resistance is:

A wire of resistance 2Omega is stretched so that its radius is halved. Determine its new resistance.

A metallic wire of length l and resistance 5 Omega is stretched to double its length. Find its new resistivity and new resistance. Assume that there is no change in the density on the stretching.

A given piece of wire oflength I, cross sectional area and resistance R is stretched uniformly to a wire oflength 21. What is the new resistance?