The intersection of the planes 2x-y-3z=8 and x+2y-4z=14 is the line L .The value of for which the line L is perpendicular to the line through (a,2,2) and (6,1,-1) is

The intersection of the planes 2x-y-3z=8 and x+2y-4z=14 is the line L .The value of alpha for which the line L is perpendicular to the line through (alpha, 2,2) and (6,11,-1) is :

Let L be the line through the intersection of the planes 3x-y+2z+1=0 and 3x-2y+z=3 . Then, the equation of the plane passing through (2, 1, 4) and perpendiculr to the line L is

The plane x + 3y + 13 = 0 passes through the line of intersection of the planes 2x - 8y + 4z = p and 3x - 5y + 4z + 10 =0 . If the plane is perpendicular to the plane 3x - y - 2z - 4 = 0 , then the value of p is equal to

The plane x + 3y + 13 = 0 passes through the line of intersection of the planes 2x - 8y + 4z = p and 3x - 5y + 4z + 10 = 0 If the plane is perpendicular to the plane , 3x - y - 2z - 4 = 0 then the value of p is equal to

A plane P passes through the line of intersection of the planes 2x-y+3z=2,x+y-z=1 and the point (1,0,1). What are the direction ratios of the line of intersection of the given planes ?

A plane P passes through the line of intersection of the planes 2x-y+3z=2.x+y-z=1 and the point (1,0,1) What are the direction ration of the line of intersection of the given planes

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0

If L_(1) is the line of intersection of the planes 2x-2y+3x-2=0x-y+z+1=0 and L_(2) is the line of the intersection of the planes x+2y-z-3=0 3x - y+2z-1=0 then the distance of the origin from the plane containing the lines L_(1) and L_(2) is