A uniform rope of `length L meters` is lying over a table. If the coefficient of friction be `mu`, then the maximum length `L_(1)` of the part of the rope which can overhang the edge without sliding is

A uniform rope of length l lies on a table . If the coefficient of friction is mu , then the maximum length l_(1) of the part of this rope which can overhang from the edge of the table without sliding down is :

A uniform rope of length l lies on a table . If the coefficient of friction is mu , then the maximum length l_(1) of the part of this rope which can overhang from the edge of the table without sliding down is : (1)/(mu) (l)/(mu+1) (mul)/(1+mu) (mul)/(1-mu)

A uniform rope of length l lies on a table. If the coefficient of friction is mu , then the maximum length L of the part of this rope which can overhang from the edge of the table without sliding down is

A uniform rope of length l lies on a table if the coefficient of friction is , then the maximum length l, of the part of this rope which can over hang from the edge of the table without sliding down is -

A uniform rope of length L lies on a table. If the coefficient of friction is mu , the maximum fractional length of the hanging part of the rope from the edge of the table without sliding down is

A homogeneous chain of length L lie on a table. If the coefficent of friction is mu , find the maximum length L_(1) of the chain which can hang from the edge of the table without the chain sliding down. (b) Consider the situation as shown in the figure. Find teh minimum value of m so that the blocks do not move.

Uniform rope of length Tlies on a table with coefficient of friction between the rope and table being u. What is the maximum length of the rope which can over hang from the edge of the table without sliding down?

Part of a uniform chain of length L is hanging out of a table. If the coefficient of friction between the chain and the table is , mu estimate the maximum length of the chain that can hang without slipping.