`3 sin x+ 4 cos x= 5implies 6 tan""(x)/(2)-9 tan^(2)""(x)/(2)=`

3sinx+4cosx=5implies6tan""(x)/(2)-9tan^(2)""(x)/(2) =

If 3sin x+4cos x=5, then 6(tan)(x)/(2)-9(sin)^(2)(x)/(2)=

(cos x )/( cos (x-2y))= lambda implies tan(x-y) tan y=

Find sin ""(x)/(2), cos "" (x)/(2) and tan "" (x)/(2) in each of the case: tan x = (-4)/(3) , x in II quadrant.

Evaluate the following integrals: int{3sin x-4cos x+(5)/(cos^(2)x)-(6)/(sin^(2)x)+tan^(2)x-cot^(2)x}dx

If "tan" x=(3)/(4),piltxlt(3 pi)/(2) , find the values of "sin"(x)/(2),cos"(x)/(2) and "tan""(x)/(2) .

Find the period of (a) (|sin4x|+|cos 4x|)/(|sin 4x-cos 4x|+|sin 4x+cos 4x|) (b) f(x)="sin"(pi x)/(n!)-"cos"(pi x)/((n+1)!) (c ) f(x)=sin x +"tan"(x)/(2)+"sin"(x)/(2^(2))+"tan"(x)/(2^(3))+ ... +"sin"(x)/(2^(n-1))+"tan"(x)/(2^(n))

(sin x) / (sin3x) + (sin3x) / (cos9x) + (sin9x) / (cos27x) = (tan27x-tan x) / (2)