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In the given figure, `AB=AC and AD` is the bisector of ? `BAC.` (i) State three pairs of equal parts in triangles `ADB and ADC.` (ii) Is `DeltaADB cong DeltaADC` ? Given reasons. (iii) Is `angleB=angleC` ? Given reasons

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`1)AB=AC`(given)
`angleBAD=angleCAD`(angle bisector)
`AD=AD`(Common)
`2) /_ABD cong /_ADC(SAS)`
`3) angleB=angleC`
(because `/_ABD cong /_ADC(SAS)`).
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