If `z_1,z_2` are roots of equation `z^2-az +a^2 = 0` then `|z_1/z_2|=`

If z_(1),z_(2) are roots of equation z^(2)-az+a^(2)=0 then |(z_(1))/(z_(2))|=

z_(1) and z_(2) are the roots of the equation z^(2) -az + b=0 where |z_(1)|=|z_(2)|=1 and a,b are nonzero complex numbers, then

If z_1, z_2 are the roots of the equation az^2 + bz + c = 0 , with a, b, c > 0, 2b^2 > 4ac gt b^2, z_1 in third quadrant , z_2 in second quadrant in the argand’s plane then, show that arg ((z_1)/z_2)=2cos^(-1)((b^2)/(4ac))^(1//2)

z_(1) and z_(2) are the roots of the equaiton z^(2) -az + b=0 where |z_(1)|=|z_(2)|=1 and a,b are nonzero complex numbers, then

z_(1) and z_(2) are the roots of the equaiton z^(2) -az + b=0 where |z_(1)|=|z_(2)|=1 and a,b are nonzero complex numbers, then

If z_1 and z_2 are the roots of the equation z^2+az+12=0 and z_1 , z_2 forms an equilateral triangle with origin. Find absa

If z_1,z_2,z_3 are any three roots of the equation z^6=(z+1)^6, then arg((z_1-z_3)/(z_2-z_3)) can be equal to

If z_1,z_2,z_3 are any three roots of the equation z^6=(z+1)^6, then arg((z_1-z_3)/(z_2-z_3)) can be equal to

Let z_1,z_2 be the roots of the equation z^2+az+12=0 and z_1, z_2 form an equilateral triangle with origin. Then, the value of absa is ________ .

Let z_(1),z_(2) be the roots of the equation z^(2)+az+12=0 and z_(1),z_(2) form an equilateral triangle with origin. Then the value of |a| is