Show that if a particle is moving in SHM, its velocity at a distance `sqrt(3)//2` of its amplitude from the central position is half its velocity in central position.

If the maximum velocity of a particle in SHM is v_0 then its velocity at half the amplitude from position of rest will be :

The ration of kinetic energy to the potential energy of a particle executing SHM at a distance equal to half its amplitude , the distance being measured from its equilibrium position is

The ration of kinetic energy to the potential energy of a particle executing SHM at a distance equal to half its amplitude , the distance being measured from its equilibrium position is

The ration of kinetic energy to the potential energy of a particle executing SHM at a distance equal to half its amplitude , the distance being measured from its equilibrium position is

A particle performing S.H.M., its velocity when the particle moves from mean to extreme position is

A particle executing SHM has amplitude of 4cm, and its acceleration at a distance of 1cm from the mean position is 3cm^(-2) . What will its velocity be when it is at a distance of 2 cm from its mean position?