Home
Class 12
MATHS
Let f(x)={(-1, -2lexlt0),(x^2-1,0lexlt2)...

Let `f(x)={(-1, -2lexlt0),(x^2-1,0lexlt2):}` if `g(x)=|f(x)|+f(|x|)` then `g(x)` in `(-2,2)` (A) not continuous (B) not differential at one point (C) differential at all points (D) not differential at two points

Promotional Banner

Similar Questions

Explore conceptually related problems

Let f(x)={(-,1, -2lexlt0),(x^2,-1,0lexlt2):} if g(x)=|f(x)|+f(|x|) then g(x) in (-2,2) is (A) not continuous is (B) not differential at one point (C) differential at all points (D) not differential at two points

Let f(x)={(-,1, -2lexlt0),(x^2,-1,0lexlt2):} if g(x)=|f(x)|+f(|x|) then g(x) in (-2,2) is (A) not continuous is (B) not differential at one point (C) differential at all points (D) not differential at two points

Consider f(x)={{:(-2",",-1lexlt0),(x^(2)-2",",0lexle2):} and g(x)=|f(x)|+f(|x|) . Then, in the interval (-2, 2), g(x) is

f(x)={(x-1, -1lexlt0),(x^2, 0ltxle1):} and g(x)=sin x. Then find h(x)=f(|g(x)|)+|f(g(x))|

Let f(x)={{:(1+(2x)/(a)", "0lexlt1),(ax", "1lexlt2):}."If" lim_(xto1) "f(x) exists, then a is "

Let f(x)={{:(1+(2x)/(a)", "0lexlt1),(ax", "1lexlt2):}."If" lim_(xto1) "f(x) exists, then a is "

Show that f(x)={[5-x,,x>=2],[x+1,,x<2] is continuous at x = 2 but not differentiable at that point.

If f(x) = 3(2x + 3)^(2//3) + 2x + 3 , then: (a) f(x) is continuous but not differentiable at x = - (3)/(2) (b) f(x) is differentiable at x = 0 (c) f(x) is continuous at x = 0 (d) f(x) is differentiable but not continuous at x = - (3)/(2)

Let f(x) be defined on [-2,2] and is given by f(x)={(-1, -2lexlt0),(x-1, 0lexle2):} and g(x)=f(|x|)+|f(x)|, then find g(x).