A copper rod of length L rotates with an angular with an angular speed `'omega' ` in a uniform magnetic field B. find the emf developed between the two ends of the rod. The field in perpendicular to the motion of the rod.

A conducting rod of length L rotates with angular speed omega in a uniform magnetic field of induction B which is perpendicular to its motion .The induceed emf developed between the two ends of the rod is

A metallic rod of length L rotates at an angular speed omega, normal to a uniform magnetic field. If the resitance of rod is R the heat dissipated is:

A copper rod AB-of length / pivoted at one end A, rotates at constant angular velocity omega , at right angles to a uniformn magnetic field of induction B. The emf, developed between the mid point of the rod and end B is

A metal rod of length I is moved with velocity v in a uniform magnetic field vec B . Emf is induced between the two ends of rod

A uniform conducting rod of length I is moving with speed v_0 in a uniform transverse magnetic field B_0 as shown in figure. The emf developed across the two ends of the rod will be

A rod of length 20 cm rotating with an angular speed of 100 revoltuions per minute in a magnetic field of strength 0.5 tesla. The potential diffeence between the two ends of the rod in volts is

A rod of length l rotates with a uniform angular velocity omega about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. The potential difference between the two ends of the rod is