For `Zn^(2+) //Zn, E^(@) =- 0.76`, for `Ag^(+)//Ag, E^(@) = -0.799V`. The correct statement is

For Zn^(2+) //Zn, E^@ =- 0. 76 V , for Ag^+ //Af E^@ =0.799 V . The correct statement is .

The standard reduction potentials of Zn and Ag in water at 298 K are, Zn^(2+)+2e^(-) rarr Zn , E^(@)= - 0.76V and Ag^(+)+e^(-) rarr Ag , E^(@) = + 0.80V Which of the following reactions take place?

At 20^(@) C, the standard oxidation potential of Zn and Ag in water are: Zn(s)rarr Zn^(2+) (aq) + 2e^(-), E^(o) = 0.76V , Ag(s) rarr Ag^(+)(aq) + E^(-) , E^(o) = - 0.80 V The standard EMF of the given reaction is: Zn+2Ag^(+)rarr 2AG+Zn^(+2)

At 20^(@) C, the standard oxidation potential of Zn and Ag in water are: Zn(s)rarr Zn^(2+) (aq) + 2e^(-), E^(o) = 0.76V , Ag(s) rarr Ag^(+)(aq) + E^(-) , E^(o) = - 0.80 V The standard EMF of the given reaction is: Zn+2Ag^(+)rarr 2AG+Zn^(+2)

Zn(s)|Zn^(2+)(aq)(0.1M)||Ag^+(aq)(0.01)|Ag(s) Given E_(Zn^(2+)//Zn)^@ = -0.76, E_(Ag^(+)//Ag)^@ = 0.80V Determine E_(cell) , if your answer is Xxx10^(-2) V then determine value of X..