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The horizontal component of the earth's ...

The horizontal component of the earth's magnetic field at a place is `3 xx 10^(-4)T` and the dip is `theta = tan^(-1)(4//3)`. A metal rod of length `0.25m` placed in the north-south position is moved at a constant speed of `10 cm//s` towards the east. The `e.m.f` induced in the rod will be :

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